Question

math help pleaseeeeeeeeeeeee. solving the triangle side values not in degree form

Answer 1

Solution:

Given;

$C=90^o,A=52^o,b=219m$

Thus;

We would apply the tangent ratio given as;

$\begin{gathered} \tan\theta=\frac{opposite}{adjacent} \\ \\ \tan52^o=\frac{BC}{219} \\ \\ BC=219\tan52^o \\ \\ BC=280.3m \end{gathered}$

Also;

$\begin{gathered} \cos\theta=\frac{adjacent}{hypotenuse} \\ \\ \cos52^o=\frac{219}{AB} \\ \\ AB=\frac{219}{\cos52^o} \\ \\ AB=355.7m \end{gathered}$