Given:
The figure of a parallelogram ABCD is given which has two triangles ABC and BCD.
Required:
We have to select the correct statement.
Explanation:
We can see that the sides AB and CD are marked by | or by one line so these sides are equal. The sides AC and BD are marked by || two or by two lines so these two sides are equal.
Now, angle A and angle D are marked by | or by one line so these two angles are equal.
Hence we have that the two triangles are similar by
[tex]side-side-angle\text{ i.e., }side-angle-side.[/tex]
Final answer:
Triangle ABC and BCD are congruent by the side-angle-side Triangle Congruence theorem.
