[tex]\begin{gathered} 3(x-2)^2-4=23 \\ 3(x-2)^2-4+4=23+4 \\ 3(x-2)^2+(-4+4)=23+4 \\ 3(x-2)^2+0=27 \\ 3\mleft(x-2\mright)^2=27 \\ (x-2)^2=\frac{27}{3} \\ (x-2)^2=9 \\ \sqrt{(x-2)^2}=\sqrt{9} \\ x-2=3 \\ x=3+2 \\ x=5 \\ \text{The value of x is 5. This value makes the equation true} \end{gathered}[/tex]
