Question

For the function g(x) = 42 – 48, find g(-4).

Answer 1

As given by the question

There are given that the expression

$g(x)=\sqrt[3]{4x-48}$

Now,

Put the value of x=-4 into the given expression

$\begin{gathered} g(x)=\sqrt[3]{4x-48} \\ g(-4)=\sqrt[3]{4(-4)-48} \\ g(-4)=\sqrt[3]{-16-48} \\ g(-4)=\sqrt[3]{-64} \\ g(-4)=((-4)^3)^{\frac{1}{3}} \\ g(-4)=-4 \end{gathered}$

Hence, the value of g(-4) is -4.