Question

What is the index of refraction of a substance if the critical angle for a ray going into Water (n=1.33) is 69.3°?1.2452.12.261.42

Answer 1

Given:

The refractive index of water is n1 = 1.33

The critical angle is

$\theta=69.3\text{ degrees}$

To find the refractive index of the substance.

Explanation:

The refractive index of the substance can be calculated as

$\begin{gathered} n2\text{ =}\frac{n1}{sin\text{ }\theta} \\ =\frac{1.33}{sin(69.3^{\circ})} \\ =\text{ 1.42} \end{gathered}$

Thus, the refractive index of the substance is 1.42