Respuesta :

[tex]\begin{gathered} \cos 165 \\ \\ \cos 165=\cos (\frac{330}{2}) \\ \\ \pm\sqrt[]{\frac{1+\cos 330}{2}} \\ \\ -\frac{\sqrt[]{1+\cos 330}}{4} \\ \frac{-\sqrt[]{6}-\sqrt[]{2}}{4} \end{gathered}[/tex]

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