Determine where X' would be if you translated X 3units to the left and 9 units down.a.) (-1, 5)b.) (-4, 4)c.) (-10, 2)d.) (-4, -5)

we are asked to find the coordinates of point X when it is translated 3 units to the left and 9 units down. This transformation is equivalent to:
[tex](x^{\prime},y^{\prime})=(x-3,y-9)[/tex]The coordinates of point X are:
[tex]X=(-1,4)[/tex]Applying the transformation we get:
[tex]\begin{gathered} (x^{\prime},y^{\prime})=(-1-3,4-9) \\ (x^{\prime},y^{\prime})=(-4,-5) \end{gathered}[/tex]Therefore, the answer is: (-4, -5)