Respuesta :

Given:

[tex]\frac{1}{2}x+\frac{1}{4}=\frac{3}{2}x+\frac{3}{4}[/tex]

Let's solve for x.

Subtract 3/2 x from both sides:

[tex]\begin{gathered} \frac{1}{2}x-\frac{3}{2}x+\frac{1}{4}=\frac{3}{2}x-\frac{3}{2}x+\frac{3}{4} \\ \\ -1x+\frac{1}{4}=\frac{3}{4} \end{gathered}[/tex]

Subtract 1/4 from both sides:

[tex]\begin{gathered} -x+\frac{1}{4}-\frac{1}{4}=\frac{3}{4}-\frac{1}{4} \\ \\ -x\text{ = }\frac{1}{2} \end{gathered}[/tex]

Divide both sides by -1:

[tex]\begin{gathered} \frac{-x}{-1}=\frac{1}{2}\div1 \\ \\ x=-\frac{1}{2} \end{gathered}[/tex]

ANSWER:

[tex]x=-\frac{1}{2}[/tex]

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