Given:
[tex]\frac{1}{2}x+\frac{1}{4}=\frac{3}{2}x+\frac{3}{4}[/tex]Let's solve for x.
Subtract 3/2 x from both sides:
[tex]\begin{gathered} \frac{1}{2}x-\frac{3}{2}x+\frac{1}{4}=\frac{3}{2}x-\frac{3}{2}x+\frac{3}{4} \\ \\ -1x+\frac{1}{4}=\frac{3}{4} \end{gathered}[/tex]Subtract 1/4 from both sides:
[tex]\begin{gathered} -x+\frac{1}{4}-\frac{1}{4}=\frac{3}{4}-\frac{1}{4} \\ \\ -x\text{ = }\frac{1}{2} \end{gathered}[/tex]Divide both sides by -1:
[tex]\begin{gathered} \frac{-x}{-1}=\frac{1}{2}\div1 \\ \\ x=-\frac{1}{2} \end{gathered}[/tex]ANSWER:
[tex]x=-\frac{1}{2}[/tex]