Respuesta :

The given equation is

[tex]2^x=3y-1[/tex]

This equation is exponential because the independent variable x is an exponent. In other words, the equation is not linear.

Now, to express the equation in standard form, we have to isolate y.

First, we sum 1 on each side.

[tex]\begin{gathered} 2^x+1=3y-1+1 \\ 3y=2^x+1 \end{gathered}[/tex]

Then, we divide the equation by 3.

[tex]\begin{gathered} \frac{3y}{3}=\frac{2^x+1}{3} \\ y=\frac{2^x+1}{3} \end{gathered}[/tex]

We have to separate the fraction.

The standard form is

[tex]y=\frac{2^x}{3}+\frac{1}{3}[/tex]

Where a = 1/3, b = 2, and c = 1/3.

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