The given equation is
[tex]2^x=3y-1[/tex]This equation is exponential because the independent variable x is an exponent. In other words, the equation is not linear.
Now, to express the equation in standard form, we have to isolate y.
First, we sum 1 on each side.
[tex]\begin{gathered} 2^x+1=3y-1+1 \\ 3y=2^x+1 \end{gathered}[/tex]Then, we divide the equation by 3.
[tex]\begin{gathered} \frac{3y}{3}=\frac{2^x+1}{3} \\ y=\frac{2^x+1}{3} \end{gathered}[/tex]We have to separate the fraction.
Where a = 1/3, b = 2, and c = 1/3.