Given,
The equation is 2x +3y -5 =0
Taking the equation as 2x + 3y =5
Taking,
[tex]\begin{gathered} x\text{ = r cos }\theta \\ y=r\text{ sin }\theta \end{gathered}[/tex]Subsituting the value of x and y in the given equation then,
[tex]\begin{gathered} 2(r\text{ cos }\theta)+3(\text{ r sin }\theta)=5 \\ r(2\text{ cos }\theta+3\sin \theta)=5_{} \\ r=\frac{5}{2\text{ cos }\theta+3\sin \theta} \end{gathered}[/tex]Hence, this is the required polar equation.