Given the area of the triangle:
[tex]A=\frac{3}{40}m^2[/tex]
You can identify in the figure provided in the exercise that the height of the triangle is:
[tex]h=\frac{1}{5}m[/tex]
The area of a triangle can be calculated using this formula:
[tex]A=\frac{bh}{2}[/tex]
Where "A" is the area, "b" is the base, and "h" is the height.
If you solve for "b", you obtain this formula:
[tex]\begin{gathered} 2A=bh \\ \\ b=\frac{2A}{h} \end{gathered}[/tex]
Therefore, knowing the Area and the height of the triangle, you can substitute them into the formula and then evaluate, in order to find the length of its base:
[tex]b=\frac{(2)(\frac{3}{40})}{\frac{1}{5}}[/tex][tex]b=\frac{\frac{6}{40}^{}}{\frac{1}{5}}[/tex][tex]b=\frac{6\cdot5}{40\cdot1}[/tex][tex]b=\frac{30}{40}[/tex][tex]b=\frac{3}{4}m[/tex]
Hence, the answer is:
[tex]b=\frac{3}{4}m[/tex]
