Question

which compound inequality is equivalent to |ax-b| > c for all real numbers a, b, and c, where $c \geqslant 0$

Answer 1

The compound inequality that represents the inequality is:

$ax-b<-c$

&

$ax-b>c$

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We have that absolute value is the "magnitude" of a value [That is, is positive].

Now, when we have the following:

$|a|Is the same as:[tex]aAnd also:[tex]-a-b$

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In other words, absolute value will always give as a solution a positive one, for example:

$|-3|=3$

Another example:

$|3|=3$