Using the given formula with the value of S = 176.4 inĀ², let's calculate the value of r:
[tex]\begin{gathered} S=4\pi r^2\to r=\sqrt[]{\frac{S}{4\pi}}=\sqrt[]{\frac{S}{12.6}} \\ \\ r=\sqrt[]{\frac{176.4}{12.6}} \\ r=\sqrt[]{14} \\ r=3.7 \end{gathered}[/tex]So the ball radius is 3.7 inches.