Given:
If you invest $10,829.00 into an account earning an annual nominal interest rate of 7.042%
[tex]\begin{gathered} P=10,829 \\ R=7.042 \\ n=4\text{ year} \\ t=11 \end{gathered}[/tex]Required:
To fid the amount after 11 years if the interest is compounded quarterly, and If the interest is compounded continuously.
Explanation:
Now,
[tex]\begin{gathered} R=7.042\% \\ \\ =\frac{7.042}{100} \\ \\ =0.07042 \end{gathered}[/tex]Therefore, The compound interest after 11 year is,
[tex]A=P(1+\frac{r}{n})^{nt}[/tex][tex]\begin{gathered} =10,829(1+\frac{0.07042}{4})^{4(11)} \\ \\ =23,338.59 \end{gathered}[/tex]So $23,338.59 will have in account after 11 years if the interest is compounded quarterly.
Now,
[tex]\begin{gathered} A=Pe^{rt} \\ \\ =10,829\times e^{0.07042(11)} \\ \\ =10,829\times(2.71828)^{0.07042(11)} \\ \\ =23,496.41 \end{gathered}[/tex]So, $29,496.41 will have in account after 11 years If the interest is compounded continuously.
Final Answer:
$23,338.59 will have in account after 11 years if the interest is compounded quarterly.
$29,496.41 will have in account after 11 years If the interest is compounded continuously.