Respuesta :

Solution:

Given:

[tex](-6+y)^2-y^2=-5x+6[/tex]

Simplifying the equation further to confirm if it is linear or not.

[tex]\begin{gathered} (-6+y)^2-y^2=-5x+6 \\ (-6+y)(-6+y)-y^2=-5x+6 \\ 36-6y-6y+y^2-y^2=-5x+6 \\ 36-12y=-5x+6 \\ Since\text{ no power exceeds one, then it is linear.} \end{gathered}[/tex]

Rewriting the equation in standard form;

[tex]\begin{gathered} 36-12y=-5x+6 \\ 5x-12y=6-36 \\ 5x-12y=-30 \end{gathered}[/tex]

Therefore, it is linear.

The equation in standard form is;

5x - 12y = -30

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