JaydrienM58422 JaydrienM58422
  • 29-10-2022
  • Physics
contestada

A spring with spring constant 58N/cm is stretched 4cm. How much force is it applying

Respuesta :

DawonQ25885 DawonQ25885
  • 29-10-2022

Answer:

232 N

Explanation:

By Hooke's law, the force applied to a spring is proportional to the stretch of the spring, so

F = kx

Where F is the force, k is the spring constant and x is how much it is stretched.

So, replacing k by 58N/cm and x by 4 cm, we get

F = (58 N/cm)(4 cm)

F = 232 N

Therefore, the force applied is 232 N

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