The Solution:
The question assumed that the readings on the thermometer are normally distributed with mean 0 degrees and standard deviation 1.00 degrees.
[tex]2.727\text{ \%=0.02727}[/tex]So, from the z-table, we have that
[tex]\begin{gathered} P(Z<0.02727)=-1.923 \\ P(Z>0.02727)=1.923 \end{gathered}[/tex]So, for readings that too low, we have
[tex]\begin{gathered} P(ZFor readings that too high, we have[tex]\begin{gathered} P(Z<1.923)\Rightarrow Z=\frac{x-\mu}{\sigma} \\ \\ 1.923=\frac{x-0}{1} \\ \\ 1.923=x \end{gathered}[/tex]To draw a sketch that shows the two readings that are cutoff values of the rejected thermometer, we have