Graphing calculator needed, quite simple to solve if you have one. I just do not have one. Thank you!

METHOD : We will use integration by part
[tex]\begin{gathered} \int udv=uv-\int vdu \\ \end{gathered}[/tex]I will modify the question by putting "1" before the In(x^2) function. See modified question in equation tab below
[tex]\begin{gathered} \int1\ln(x^2)dx \\ u=\ln(x^2) \\ \frac{du}{dx}=\frac{2x}{x^2}=\frac{2}{x} \\ \\ dv=1 \\ v=\int1dx \\ v=x \\ \end{gathered}[/tex][tex]\begin{gathered} \int1\ln(x^2)=x\ln x^2-\int x\frac{2dx}{x} \\ \\ =x\ln x^2-\int2dx \\ \\ =x\ln x^2-2x \end{gathered}[/tex][tex]\begin{gathered} \int_2^{x^3}[x\ln x^2-2x]dx \\ \\ [x^3\ln(x^3)^2-2(x^{`3})]-[2\ln2^2-2(2)] \\ x^3\ln x^6-2x^3-2\ln4-4 \end{gathered}[/tex]