Question

Suppose you own a toy company... Toy cars sell for $6.20 and toyswords sell for $9.70 . Perhaps you are going to package up the cars and swords and ship them to a store in your own car. You know you can fit no more than 74 toys in your car. With these constraints , can you take enough toys to the store to sell at least $850 worth?-yes-no

Answer 1

Mathematics → Linear Equations in the Real World → Problem-Solving Models

Let:

"a" be the number of toy cars sold

"b" be the number of toywords sold

The prices of one unit are:

a = $6.20

b = $9.70

If you can fit only 74 toys in your car, a + b ≤ 74.

The situation that gives you the greater amount of money, is selling 74 (maximum number of toys) toywords (since toywords is more expensive).

If you sell 74 units of "b", you get:

$\begin{gathered} 74*9.70 \\ 717.8 \end{gathered}$

The maximum amount of money you can get is $717.80. So, you can not get $850.

Answer: No.