Answer:
Concept:
Represent the statement below as
y varies inversely as the square root of x
[tex]y\propto\frac{1}{\sqrt[]{x}}[/tex]Note:
When the proportionality sign is changed to an equal to sign, a constant k is introduced
By applying this, we will have
[tex]\begin{gathered} y\propto\frac{1}{\sqrt[]{x}} \\ y=\frac{k}{\sqrt[]{x}}----(1) \end{gathered}[/tex]Step 2:
Substitute the values x=64 and y =9 in equation (1) above
[tex]\begin{gathered} y=\frac{k}{\sqrt[]{x}}----(1) \\ 9=\frac{k}{\sqrt[]{64}} \\ 9=\frac{k}{8} \\ \text{cross multiply,we will have} \\ k=9\times8 \\ k=72 \end{gathered}[/tex]Step 3:
Re place the value of k=72 in equation (1)
[tex]\begin{gathered} y=\frac{k}{\sqrt[]{x}} \\ y=\frac{72}{\sqrt[]{x}} \end{gathered}[/tex]Hence,
The final answer is
[tex]\Rightarrow y=\frac{72}{\sqrt[]{x}}[/tex]