Question

solve the following system of equations algebraically:y=x²-4x+2 y=x+2

Answer 1

To solve the given system of equations, make both expressions for y equal, then solve for x:

$\begin{gathered} x^2-4x+2=x+2 \\ x^2-4x+2-2=x \\ x^2-4x=x \\ x^2-4x-x=0 \\ x^2-5x=0 \\ x(x-5)=0 \\ x1=0 \\ x2-5=0 \\ x^2=5 \end{gathered}$

x has 2 values, x=0 and x=5.