a circle is centered on point B. Points A,C and D lie on its circumfrence.

To solve this problem, we have to use this theorem
[tex]m\angle ADC=\frac{1}{2}m\angle\text{ABC}[/tex]Replacing the given angle, we have
[tex]\begin{gathered} 23=\frac{1}{2}m\angle ABC \\ m\angle ABC=46 \end{gathered}[/tex]