Question

What would the charge need to be on an object so that a 5.2 x 10^-6 Ccharge that is separated by a distance of.28 m would experience anattractive force of 220 N?(Don't forget your units!)Your answer

Answer 1

Answer:$q_2\text{ = }3.69\text{ }\times10^{-4}C$Explanations:

According to Coulomb's law, the force of attraction between two different charges q₁ and q₂ and separated by a distance r is given by the formula:

$F\text{ = }\frac{kq_1q_2}{r^2}$$q_1\text{ = 5.2 }\times10^{-6}C$

The force, F = 220N

The distance separating the two charges, r = 0.28

$F\text{ = }\frac{kq_1q_2}{r^2}$

To find the charge second q₂, substitute q₁, k, F, and r into the formula above

$\begin{gathered} 220\text{ = }\frac{9\times10^9\times5.2\times10^{-6}\times q_2}{0.28^2} \\ 220\text{ = }\frac{46800\times q_2}{0.0784} \\ 220\times0.0784\text{ = 46800 }\times q_2 \\ q_2\text{ = }\frac{220\times0.0784}{46800} \\ q_2\text{ = }3.69\text{ }\times10^{-4}C \end{gathered}$