I’m struggling to understand the next part cause I thought it was 28 but I guess not

The equation of a straight line is given in the form:
[tex]y=mx+b[/tex]where m is the slope and b is the intercept on the y axis.
The question already provides the value of the slope to be:
[tex]m=28[/tex]Therefore, the value of b can be gotten by substituting any pair of x and y values into the equation:
[tex]\begin{gathered} y=28x+b \\ Take\text{ }(x,y)=(1,28) \\ \therefore \\ 28=28(1)+b \\ 28=28+b \\ b=28-28 \\ b=0 \end{gathered}[/tex]The unknown value is 0.
The equation will be:
[tex]\begin{gathered} y=28x+0 \\ or \\ y=28x \end{gathered}[/tex]