Question

A car starts from rest and accelerates at 9.54m/s2 for 6.5sec. What is the distance covered by the car?

Answer 1

Answer:

Explanation:

If a body starts from rest, with an acceleration of a for time t, then the distance D covered by is given by

$D=\frac{1}{2}at^2$

Now, in our case we have a = 9.54 m/s^2 and t = 6.5 s; therefore,

$D=\frac{1}{2}\cdot(9.54m/s^2)\cdot(6.5s)^2$

which upon simplification gives

$\boxed{D=201.5325m}$

Hence, the distance covered by the car is about 202 meters.