Question

please mark the questions right or wrong. if the answer is wrong, write the correct answer.

Answer 1

Exponentials and square roots

We know that:

$\sqrt[n]{7}=7^{\frac{1}{n}}$

In this case, by convention:

$\sqrt[2]{7}=\sqrt[]{7}$

Then,

$\sqrt[]{7}=\sqrt[2]{7}=7^{\frac{1}{2}}$

Answer: right