Question

If ABCD is dilated by a factor of 2, thecoordinate of D' would be:543С2.B.-8-7-6-5-4-3-2-1 01234567891011-1A-2D-3D' = ([?], [ ]=Enter

Answer 1

Solution:

Given:

A graph showing a quadrilateral ABCD.

From the graph, the coordinates of the points are given as;

$\begin{gathered} A=(-3,-1) \\ B=(-1,1) \\ C=(2,2) \\ D=(3,-2) \end{gathered}$

If ABCD is dilated by a factor of 2, this means each of the points will have their coordinates multiplied by 2 to produce an enlarged image of ABCD.

Hence, the dilated image will have the following coordinates;

$\begin{gathered} A^{\prime}=(-6,-2) \\ B^{\prime}=(-2,2) \\ C^{\prime}=(4,4) \\ D^{\prime}=(6,-4) \end{gathered}$

Therefore, the coordinate of D' = (6, -4)