What is half the sum of the remainder of 71 divided by 11 and the quotient of 143 divided by 11?

Solution:
Given;
What is half the sum of the remainder of 71 divided by 11 and the quotient of 143 divided by 11?
71 divided by 11 is
[tex]\begin{gathered} \frac{71}{11}=6\frac{5}{11} \\ The\text{ remainder is 5} \end{gathered}[/tex]143 divided by 11 is
[tex]\begin{gathered} \frac{143}{11}=13 \\ The\text{ quotient is 13} \end{gathered}[/tex]The sum of the remainder of 71 divided by 11 and the quotient of 143 divided by 11 is
[tex]=5+13=18[/tex]Thus, the half of the sum is
[tex]=\frac{1}{2}\times18=9[/tex]Hence, the answer is 9