Answer
The new pressure = 69.2 atm
Explanation
Given:
Initial volume, V₁ = 284 L
Initial pressure, P₁ = 159 atm
Final volume, V₂ = 653 L
What to find:
The new pressure, P₂ when the volume changes to 653 L.
Step-by-step solution
The new pressure, P₂ when the volume changes to 653 L can be calculated using Boyle's law equation.
[tex]\begin{gathered} P_1V_1=P_2V_2 \\ \\ \Rightarrow P_2=\frac{P_1V_1}{V_2} \end{gathered}[/tex]
Putting the values of the given parameters into the equation, we have
[tex]P_2=\frac{159\text{ }atm\times284\text{ }L}{653\text{ }L}=\frac{45156}{653}=69.2\text{ }atm[/tex]
The new pressure = 69.2 atm
