Given:
The initial volume of the balloon, V₁=419 cm³=419×10⁻⁶ m³
The initial temperature of the balloon, T₁=570 K
The final temperature of the balloon, T₂=210 K
To find:
The final volume of the balloon.
Explanation:
From Charle's law,
[tex]\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \Rightarrow V_2=\frac{V_1}{T_1}\times T_2 \end{gathered}[/tex]On substituting the known values,
[tex]\begin{gathered} V_2=\frac{419\times10^{-6}}{570}\times210 \\ =154.4\times10^{-6}\text{ m}^3 \\ =154.4\text{ cm}^3\text{ } \end{gathered}[/tex]Final answer:
The volume of the balloon will be 154.4 cm³
