[tex]\begin{gathered} \text{Angle BAC=}\theta\text{=2radians} \\ BC=6\operatorname{cm} \\ r=\text{?} \\ BC=r\theta \\ r=\frac{BC}{\theta} \\ r=\frac{6cm}{2} \\ r=3\operatorname{cm} \\ \text{The value of the radius is 3cm} \\ 3. \\ \text{The measure of the angle could be -140\degree} \\ \\ 7. \\ x=12\sin (60) \\ x=6\sqrt{3} \\ y=12\cos (60) \\ y=6 \\ \text{The value of x is }6\sqrt[]{3}\text{ and y is 6} \\ \\ 8.\text{ } \\ x=10 \\ x=\sqrt{(5)^2^{}+(5\sqrt[]{3})^2} \\ x=\sqrt[]{25+(25\cdot3)} \\ x=\sqrt[]{25+75} \\ x=\sqrt{100} \\ x=10,\text{ hence } \\ \text{The value of a is 5 and b is 5}\sqrt[]{3} \end{gathered}[/tex]
