The equatioon is solved as follows.
[tex]\begin{gathered} \frac{4(x+3)(x+1)}{(x+5)(x-5)} \\ \text{Substitute 3 for x in the equation} \\ \frac{4(3+3)(3+1)}{(3+5)(3-5)} \\ \frac{4\ast6\ast4}{8\ast-2} \\ Simplify \\ \frac{6}{-1}=-6 \end{gathered}[/tex]The value of equation at x is -6
