Question

Area of the rectangle: __ square units.Area of the triangle: __ square units.Area of the figure: __ square units.

Answer 1

We will solve as follows:

*Area of the rectangle:

$A_r=(4)(5)\Rightarrow A_r=20$

*Area of the triangle:

$A_t=\frac{(4)(3)}{2}\Rightarrow A_t=6$

*Area of the figure:

$A_f=A_r+A_t\Rightarrow A_f=20+6$$\Rightarrow A_f=26$