We will determine the volume of each tank as follows:
[tex]\begin{gathered} V_{t1}=\pi(10m)^2(3m)\Rightarrow V_{t1}\approx942m^3 \\ \\ V_{t2}=\pi(5m)^2(12m)\Rightarrow V_{t2}\approx942m^3 \end{gathered}[/tex]
From this, we will have that both options will have the same volume, and that volume is approximately 942 m^3.
