Answer:
1.0
Explanation:
To find the variance of the probability distribution, we make use of the formula:
[tex]\sigma^2=\sum x^2P(x)-\mu^2[/tex]
First, find the expected value, i.e mean of the distribution.
[tex]\mu=\sum xP(x)[/tex]
From the table, the mean of the distribution = -0.60.
Next, we find the variance.
From the table:
[tex]\sum x^2P(x)=1.36[/tex]
Therefore:
[tex]\implies\sigma^2=\sum x^2P(x)-\mu^2=1.36-(-0.60)^2=1.36-0.36=1[/tex]
The variance of the probability distribution is 1.0
