Find the difference between the cost of 2 line ad and the cost of a 3 line ad.

The piecewise function is given to be:
[tex]a(x)=\begin{cases}45,\text{ when }x\le3 \\ 45+9(x-3),\text{when }x>3\end{cases}[/tex]QUESTION A
For a 2 line ad, the first equation will be used. Therefore:
[tex]a(2)=45[/tex]For a 3 line ad, the first equation will be used. Therefore:
[tex]a(3)=45[/tex]Therefore, the difference is:
[tex]a(3)-a(2)=45-45=0[/tex]The difference is 0.
QUESTION B
For a 10 line ad, we will use the second equation:
[tex]a(x)=45+9(x-3)[/tex]At x = 10,
[tex]\begin{gathered} a(10)=45+9(10-3)=45+9(7) \\ a(10)=45+63=108 \end{gathered}[/tex]The cost of a 10 line ad is 108.
QUESTION C
For an 11 line ad, we will use the second equation.
At x = 11,
[tex]\begin{gathered} a(11)=45+9(11-3) \\ a(11)=117 \end{gathered}[/tex]The cost of an 11 line ad is 117.