Question

The measure of DF the center of the given circle

Answer 1

Solution:

Given the circle;

$|OF|\cong|OE|=r$

Thus;

$\triangle FOE\text{ is isosceles triangle}$

Then;

$\begin{gathered} \angle OFE=38^o \\ \\ \angle Arc\text{ }DF=38^o+38^o..............(\text{ An exterior angle of a triangle is equal to the sum of the two interior opposite angles\rparen} \\ \\ \angle Arc\text{ }DF=76^o \end{gathered}$

CORRECT OPTION: B