Option A
$90 + $4 each time
Option B
$13 each time
Procedure
Equations
[tex]\begin{gathered} (1)\to C=90+4t \\ (2)\to C=13t_{} \\ \\ 90+4t=13t \\ 13t-4t=90 \\ 9t=90 \\ t=\frac{90}{9} \\ t=10 \end{gathered}[/tex]The cost would be
[tex]\begin{gathered} C=90+4\cdot10 \\ C=90+40 \\ C=130 \end{gathered}[/tex]The answer would be $130