Question

Brenda left the hardware store andtraveled toward the train station at anaverage speed of 34 km/h. Sometime laterScott left traveling in the same directionbut at an average speed of 51 km/h. Aftertraveling for four hours Scott caught upwith Brenda. How long did Brenda travelbefore Scott caught up?

Answer 1

Answer:

Brenda have travelled for 6 hours before Scott caught up with her and she have covered 204 km.

Explanation:

Given;

Brenda's speed = 34 km/h

Scott's speed = 51 km/h

Scott's time of travel = 4 hours

The distance covered by Scott is;

$\begin{gathered} d_1=51\text{ km/h}\times4\text{ h} \\ d_1=204\text{ km} \end{gathered}$

Since Scott have caught up with Brenda after 4 hours, the distance Brenda have travelled before Scott caught up with her is equal to the distance Scott travelled.

$d_2=d_1=204\text{ km}$

Brenda's time of travel is;

$\begin{gathered} t=\frac{204\text{ km}}{34\text{ km/h}} \\ t=6\text{ hours.} \end{gathered}$

Therefore, Brenda have travelled for 6 hours before Scott caught up with her and she have covered 204 km.