Given a regular hexagon with side length of 24 in, find:a. the measure of a central angleb. the apothemc. the area(round each answer to the nearest hundredth)

The central angle of a regular polygon of n sides is given as:
[tex]\theta\text{ = }\frac{360}{n}[/tex]Since this is a regular hexagon, there are 6 sides
n = 6
Therefore:
[tex]\begin{gathered} \theta\text{ = }\frac{360}{6} \\ \theta=60^0 \end{gathered}[/tex]The area of a regular hexagon is given as:
[tex]\begin{gathered} \text{Area = }\frac{3\sqrt[]{3}}{2}a^2 \\ \text{where a is the side length} \end{gathered}[/tex]The side length of the hexagon is 24 in.
That is, a = 24
Substitute a = 34 into the formula for the area above:
[tex]\begin{gathered} \text{Area = }\frac{3\sqrt[]{3}}{2}\times24^2 \\ \text{Area = }\frac{3\sqrt[]{3}}{2}\times576 \\ \text{Area = }1496.49in^2 \end{gathered}[/tex]The Apothem = (2 x Area) / Perimeter
Perimeter of a regular hexagon = 6a
Perimeter = 6 x 24
Perimeter = 144 in
Apothem = (2 x 1496.49) / 144
Apothem = 20.79