The correct answer is
[tex]3y+x=0[/tex]If we write this solution in another form , it can have
[tex]y=\frac{-1}{3}x\text{ or 3y=-x}[/tex]This is working;
[tex]\text{Slope}=\frac{y_2-y_1}{x_2-x_1}=\frac{0-1}{0--3}=\frac{-1}{3}[/tex]The equation of the line is;
[tex]\begin{gathered} y-y_1=slope(x-x_1) \\ y-1=\frac{-1(x--3)}{3} \\ 3(y-1)=-1(x+3) \\ 3y-3=-x-3 \\ 3y=-x \\ y=\frac{-x}{3} \end{gathered}[/tex]