Given that triangles PIC and GRA are similar, then the next proportion must be satisfied:
[tex]\frac{PI}{GR}=\frac{IC}{RA}=\frac{PC}{GA}[/tex]
Replacing with data and solving for AG,
[tex]\begin{gathered} \frac{91}{119}=\frac{104}{AG} \\ 91\cdot AG=104\cdot119 \\ AG=\frac{12376}{91} \\ AG=136 \end{gathered}[/tex]
Replacing with data and solving for CI,
[tex]\begin{gathered} \frac{91}{119}=\frac{CI}{102} \\ \frac{91\cdot102}{119}=CI \\ \frac{9282}{119}=CI \\ 78=CI \end{gathered}[/tex]
