For the information given in the statement, let be
A = the hours that volunteer A worked
B = the hours that volunteer B worked
C = the hours that volunteer C worked
Then, you have the following system of linear equations
[tex]\begin{cases}148A+114B+139C=792\text{ (1)} \\ A+B+C=6\text{ (2)} \\ B+C=2A\text{ (3)}\end{cases}[/tex]Now, using the elimination method you have
*First multiply equation (2) by -148