Question

What is the coordinate of the center of the following circle: x2 + 2x + y2 − 8y − 6 = 0

Answer 1

We will have the following:

$x^2-2x+y^2-8y-6=0\Rightarrow(x-1)^2+(y-4)^2=23$

So, the center of the circle is located at (1, 4).