Question

An object moving at a velocity of 32 m/s slows to a stop in 4 seconds. What was its acceleration?v = vo + at

Answer 1

ANSWER

$-8m/s^2$

EXPLANATION

Parameters given:

Initial velocity, v0 = 32 m/s

Final velocity, v = 0 m/s

Time, t = 4 seconds

To find the acceleration, apply the formula for acceleration:

$a=\frac{v-v0}{t}$

Therefore, we have that:

$\begin{gathered} a=\frac{0-32}{4} \\ a=\frac{-32}{4} \\ a=-8m/s^2 \end{gathered}$

That is its acceleration.