Question

True or False?x^2 + 6x + 9 factors into (x+3)^2

Answer 1

To prove if the expression factors into the squared (x+3) we can expand the square

$\begin{gathered} (x+3)^2=(x+3)\cdot(x+3) \\ \\ (x+3)\cdot(x+3) \\ x^2+3x+3x+9 \\ x^2+6x+9 \end{gathered}$

since the expression is the same we can say that the statement is true.