We are given the following information
There are two investments totaling $13,500.
Nelson lost 5% on one and earned 7% on the other.
The net annual receipts were $327.
Let x and y represent the amount of each investment.
Using the above information, we can set up the following two equations
[tex]\begin{gathered} x+y=13,500\quad eq.1 \\ -0.05x+0.07y=327\quad eq.2 \end{gathered}[/tex]
Let us solve the above system of linear equations using the substitution method.
Re-write eq.1 in terms of x or y
[tex]y=13,500-x\quad eq.1[/tex]
Now, substitute eq.1 into eq.2
[tex]\begin{gathered} -0.05x+0.07y=327 \\ -0.05x+0.07(13,500-x)=327 \\ -0.05x+945-0.07=327 \\ -0.12x+945=327 \\ -0.12x=327-945 \\ -0.12x=-618 \\ x=\frac{-618}{-0.12} \\ x=5,150 \end{gathered}[/tex]
Finally, substitute the value of x into eq.1 to find the value of y
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