Question

62 + 24(2) = 5x + 4x

Answer 1

We are given the following equation:

$6^2+24(2)\le\frac{5x+4x}{2}$

First we will solve the square:

$36+24(2)\le\frac{5x+4x}{2}$

Now we will solve the product:

$36+48\le\frac{5x+4x}{2}$

Now we will add the numbers:

$84\le\frac{5x+4x}{2}$

Now we will multiply both sides by 2:

$\begin{gathered} 2\times84\le2\times\frac{5x+4x}{2} \\ 168\le5x+4x \end{gathered}$

Now we add the terms on the right side:

$168\le9x$

Now we will divide both sides by 9:

$\begin{gathered} \frac{168}{9}\le\frac{9x}{9} \\ \frac{56}{3}\le x \end{gathered}$