SOLUTION:
Case: Intercept
Method:
the y-intercept is the value of y at x=0
[tex]\begin{gathered} y(x)=x^2+2x-8 \\ y(0)=0^2+2(0)-8 \\ y(0)=-8 \end{gathered}[/tex]x-intercept
[tex]\begin{gathered} y=x^2+2x-8 \\ x^2+2x-8=0 \\ x^2+4x-2x-8=0 \\ x(x+4)-2(x+4)=0 \\ (x+4)(x-2)=0 \\ x=-4,x=2 \end{gathered}[/tex]The x-intercepts are: -4 and 2
Final answer:
Yes,
the y-intercept is -8
The x-intercepts are: -4 and 2
