To solve for the quadratic equation given, we shall use the quadratic equation formula as follows;
[tex]\begin{gathered} x^2+6x-6=0 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where a=1, b=6, and c=-6} \\ x=\frac{-6\pm\sqrt[]{6^2-4(1)(-6)}}{2(1)} \\ x=\frac{-6\pm\sqrt[]{36+24}}{2} \\ x=\frac{-6\pm\sqrt[]{60}}{2} \\ x=\frac{-6\pm7.75}{2} \\ x=\frac{-6+7.75}{2},x=\frac{-6-7.75}{2} \\ x=0.875,x=-6.875 \end{gathered}[/tex]The answers are approximately x = 0.87, OR x = -6.87
